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<pre>Querying <a href="http://dbpedia.org/sparql">http://dbpedia.org/sparql</a></pre>
 
<pre> </pre>
<pre>PREFIX yagoc:		<http://dbpedia.org/class/yago/></pre>
<pre>SELECT COUNT(?set1) where { ?set1 a yagoc:ProgrammingLanguage106898352 . }</pre>
result = 336
<pre>PREFIX dbpp:		<http://dbpedia.org/property/></pre>
<pre> SELECT COUNT(?set2) where { ?set2 dbpp:wikiPageUsesTemplate <http://dbpedia.org/resource/Template:Infobox_programming_language> }</pre>
 
result = 426
disjunction, language is in set1 OR set2
<pre>PREFIX dbpp:		<http://dbpedia.org/property/> PREFIX yagoc:		<http://dbpedia.org/class/yago/> SELECT count(?s) where { { ?s dbpp:wikiPageUsesTemplate <http://dbpedia.org/resource/Template:Infobox_programming_language> . } UNION { ?s a yagoc:ProgrammingLanguage106898352 . } }</pre>
result = 762
conjunction, language is in set1 AND set2
<pre>PREFIX dbpp:		<http://dbpedia.org/property/> PREFIX yagoc:		<http://dbpedia.org/class/yago/> SELECT COUNT(?set) where { ?set a yagoc:ProgrammingLanguage106898352 . ?set dbpp:wikiPageUsesTemplate <http://dbpedia.org/resource/Template:Infobox_programming_language> . }</pre>
result = 178
 
<pre>PREFIX dbpp:		<http://dbpedia.org/property/> PREFIX yagoc:		<http://dbpedia.org/class/yago/></pre>
<pre> SELECT count(?and) where { { ?or dbpp:wikiPageUsesTemplate <http://dbpedia.org/resource/Template:Infobox_programming_language> . } UNION { ?or a yagoc:ProgrammingLanguage106898352 . } ?and dbpp:wikiPageUsesTemplate <http://dbpedia.org/resource/Template:Infobox_programming_language> . ?and a yagoc:ProgrammingLanguage106898352 .</pre>
<pre> FILTER(?and = ?or)</pre>
<pre>}</pre>
 
result = 356!?
Took me a long while to realise what that number represents, definitely time for a break...
What I'm trying to find (if it's possible) are queries to look at the difference between the sets above, the 762 - 178 = 584 part. I'm hoping something along the lines of <a href="http://hyperdata.org/wiki/Sparql_Recipes" title="sparql recipes">Finding Resources that don't have a certain property</a> might work. If anyone knows an idiom that'll work (or knows that it isn't possible) please ping me.